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7a^2+6=-43a
We move all terms to the left:
7a^2+6-(-43a)=0
We get rid of parentheses
7a^2+43a+6=0
a = 7; b = 43; c = +6;
Δ = b2-4ac
Δ = 432-4·7·6
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-41}{2*7}=\frac{-84}{14} =-6 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+41}{2*7}=\frac{-2}{14} =-1/7 $
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